What is the velocity in a 25" x 8" duct section with a flow of 1450 cfm?

Study for the North Carolina Heating Group 3 (H3) Class 1 Test. Use flashcards and multiple choice questions, each with hints and explanations. Prepare thoroughly!

Multiple Choice

What is the velocity in a 25" x 8" duct section with a flow of 1450 cfm?

Explanation:
To determine the velocity of air in a duct, you can use the formula: \[ \text{Velocity} = \frac{\text{Flow Rate (CFM)}}{\text{Area (sq ft)}} \] First, you need to calculate the area of the duct section. The given dimensions of the duct are 25 inches by 8 inches. To convert these dimensions into feet, you need to divide by 12: - Height: \( \frac{25 \text{ inches}}{12} = 2.0833 \text{ feet} \) - Width: \( \frac{8 \text{ inches}}{12} = 0.6667 \text{ feet} \) Next, you can calculate the area of the duct in square feet: \[ \text{Area} = \text{Height} \times \text{Width} = 2.0833 \text{ ft} \times 0.6667 \text{ ft} \approx 1.3889 \text{ sq ft} \] Now that we have the area, we can substitute this and the flow rate into the velocity formula. Given the flow rate is 1450 CFM

To determine the velocity of air in a duct, you can use the formula:

[

\text{Velocity} = \frac{\text{Flow Rate (CFM)}}{\text{Area (sq ft)}}

]

First, you need to calculate the area of the duct section. The given dimensions of the duct are 25 inches by 8 inches. To convert these dimensions into feet, you need to divide by 12:

  • Height: ( \frac{25 \text{ inches}}{12} = 2.0833 \text{ feet} )

  • Width: ( \frac{8 \text{ inches}}{12} = 0.6667 \text{ feet} )

Next, you can calculate the area of the duct in square feet:

[

\text{Area} = \text{Height} \times \text{Width} = 2.0833 \text{ ft} \times 0.6667 \text{ ft} \approx 1.3889 \text{ sq ft}

]

Now that we have the area, we can substitute this and the flow rate into the velocity formula. Given the flow rate is 1450 CFM

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